This site will tell you all you need to know about your LED circuits, however you need the datasheet of the LED's you're using.
LED series parallel array wizard
Forward voltage is sometimes listed as voltage drop.
Below is an explanation of how that calculator arrived at its value. You don't need to know this stuff, but I thought I'd put it in there for those of you who want to know it.
The voltage drop is important because it tells you how many LED's can be run on the same strand, called "in series". Voltage drop adds together with each LED in series. If you have a voltage source of 12v, 5 LED's, and your voltage drop is 2.2 for each LED (11V total), then you have a net voltage of 1 volt. This net voltage is what is used to calculate the resistor needed for that strand. If the LED's are rated at 20mA (.020A), with your 1V (net voltage) you would need a resistor value of:
Ohm's Law: Volt (V) = Current (A) X Resistance (Ohm)
Rewritten to solve for Ohms: Ohms = V/A = 1/.020 = 50 ohm resistor
Since 50 ohms is not a common value, you would move to the closest higher value available. This will reduce the current a little, but it shouldn't affect the brightness of your LED much, unless you go much higher in resistance. You don't want to move down, as this will allow more current to flow than the rated 20mA, and could cause the LED's life to shorten.
So, in this case the most LED's you can run in a single strand is 5. If you need more than 5, you just put them on another strand. Remember that if you have fewer than 5 LED's on the new strand, the net voltage will be higher and therefore need's a higher resistor to limit the current to 20mA.
Following these rules will give you the brightest LED's possible, that will last the longest and give the longest battery life. Sure you could do 5 strings of single LED's with a 560 Ohm resistor for each LED, but that requires 5x20 = 100mA of current, which will last 1/5as long for the same result.
LED series parallel array wizard
Forward voltage is sometimes listed as voltage drop.
Below is an explanation of how that calculator arrived at its value. You don't need to know this stuff, but I thought I'd put it in there for those of you who want to know it.
The voltage drop is important because it tells you how many LED's can be run on the same strand, called "in series". Voltage drop adds together with each LED in series. If you have a voltage source of 12v, 5 LED's, and your voltage drop is 2.2 for each LED (11V total), then you have a net voltage of 1 volt. This net voltage is what is used to calculate the resistor needed for that strand. If the LED's are rated at 20mA (.020A), with your 1V (net voltage) you would need a resistor value of:
Ohm's Law: Volt (V) = Current (A) X Resistance (Ohm)
Rewritten to solve for Ohms: Ohms = V/A = 1/.020 = 50 ohm resistor
Since 50 ohms is not a common value, you would move to the closest higher value available. This will reduce the current a little, but it shouldn't affect the brightness of your LED much, unless you go much higher in resistance. You don't want to move down, as this will allow more current to flow than the rated 20mA, and could cause the LED's life to shorten.
So, in this case the most LED's you can run in a single strand is 5. If you need more than 5, you just put them on another strand. Remember that if you have fewer than 5 LED's on the new strand, the net voltage will be higher and therefore need's a higher resistor to limit the current to 20mA.
Following these rules will give you the brightest LED's possible, that will last the longest and give the longest battery life. Sure you could do 5 strings of single LED's with a 560 Ohm resistor for each LED, but that requires 5x20 = 100mA of current, which will last 1/5as long for the same result.
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