Recent content by klippard

  1. K

    Doctor Who Classic Series Roundel

    I've been working on re-creating a classic Doctor Who series roundel from scratch, and finally making some progress. I am looking for advice from experienced fiberglass (GRP) members. The problem I am having is air bubbles being trapped between the surface veil and the mold. Sometimes these...
  2. K

    Baker Roundel Project - CAD Help needed

    Some progress has been made. I'm working on making some subtle changes to the former that should improve the profile accuracy. A V2 plaster roundel was created with the old former, and it could be use to make a mould. I'm going to wait and see how V3 turns out before making any moulds since...
  3. K

    Baker Roundel Project - CAD Help needed

    Here are some pictures of the plaster roundel and brass former that I used to make it. This attempt came out rough in places, and the plaster never got hard on the surface. This is probably due to a combination of bad plaster and the fact that I was having to mist water on the surface to keep...
  4. K

    Baker Roundel Project - CAD Help needed

    I tweaked the drawing a bit to make it more accurate to Purple's measurements. The result is a slightly deeper roundel than previously posted. Updated dimensional drawing: Here is the finished product, as close I can get it to the known measurements. Here is a link to the final Google...
  5. K

    Baker Roundel Project - CAD Help needed

    Well, they are very close to Purple's drawing but not 100% exact. Here are the measurements. I can tweak the drawing for you if you like. Just let me know what you want changed. I also hollowed out the thicker parts of the drawing to maybe reduce the cost of 3D-printing. I'll post the final...
  6. K

    Baker Roundel Project - CAD Help needed

    I based the roundel cross section on the graphic that Teletran posted over at the TARDIS builders site. Then I traced the graphic using lines and arcs to get a solid cross section in Google Sketchup. Then I extruded the cross section into a circle, and here is the result. Well, it's...
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